Answer:
30214 N
Step-by-step explanation:
To start with, we solve this problem by applying Archimedes’ principle. We say that the weight of the truck and the weight of load is equal to the weight of the additional water displaced when the truck and the load moves onto the barge. Thus,
Volume of water displaced = 10.00 m * 8.00 m * 0.0385 m = 3.08 m³.
Density of water = 1000kg/m³
Mass of water displaced = volume * density
Mass of water displaced = 3.08 * 1000 = 3080 kg
Weight of water displaced (mg) = 3080 x 9.81 = 30214 N
Therefore, the Weight of truck + load = 30214 N