Answer:
c. equal to 80
Explanation:
Given that:
The population mean = 80
The standard deviation is = 6
The sample mean = 85
The objective is to find the probability that is less than 85




From the standard normal table
P(X <85) = 0.7977
P(X< 85) = 79.77%
P(X< 85) = 80%
Therefore, The adjusted value of the true mean in population S that would result in approximately 80% of parts from that population being given a passing score is: equal to 80 .