Question

For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is:_______a. K = [H+][NO2-]/[HNO2] b. K = [H+][N3+][O2-]^2/ [HNO2]c. K= [H+][NO2-] d. K = [H+]^2[NO-]/[HNO2]

Answer 1

a. K = [H+][NO2-]/[HNO2]

Step-by-step explanation:

The computation of the expression of the equilibrium constant is shown below:

Given that the weak acid is HNO_2 that exist in the solution that aqueous

The dissociation equation of
`HNO_2`

`HNO_2(aq) \rightarrow NO_(2)^(-) (aq) + H^(+)(aq)`

Now

Acidionization constant i.e.

`k_a = ([NO_(2)^(-)][H^(+)])/(HNO_(2))`

Therefore the correct option is a.

Hence, the same is to be considered