Question

Indicate the equation of the given line in standard form, in the equation box below.

The line through (-3,4) and perpendicular to a line that has a slope 2/5

Answer 1

Perpendicular lines have slopes that are negative reciprocals of each other, so the equation of the line in point-slope form is:

`y-4=-(5)/(2)(x+3)`

Rewriting this in standard form,

`2y-8=-5(x+3) \\ \\ 2y-8=-5x-15 \\ \\ \boxed{5x+2y=-7}`