Question

If a 3.0 M solution of glucose (C6H12O6), a 2.0 M solution of Na2SO4 and a 1.0 M solution of (NH4)3PO4, is made, which solution will have the lowest vapor pressure, highest boiling point, and lowest freezing point?

Answer 1

Answer: Na2SO4

Step-by-step explanation:

Answer 2

`Na_(2)SO_(4)`

Step-by-step explanation:

In the case when there are more ions present in the solution so that solution contains less vapour pressure, high boiling point and less freezing point

Given that

`Na_(2)SO_(4) \rightarrow 2Na+ + SO_(4)^(-2)`

Now the ions present would be

= 2.0 × 3

= 6 ions

These ions represent the greater among all the solutions available

Therefore the
`Na_(2)SO_(4)` is the right answer

The same is to be considered