Question

Calculate the force output by the larger piston of a hydraulic lift when a force of 800 N is exerted on the smaller piston. The areas of the two pistons are 20 cm2 and 500 cm2.

Answer 1

F2= 5kN

step by step explanation

Note the second diameter was used as 50cm and not 500cm

given

F1=800N

D1=20cm

A1=πD1^2/4

=3.142*20^2/4

=314.2cm^2

D2= 50cm

A2=πD2^2/4

=3.142*50^2/4

=1963.75cm^2

The pressure applied on the smaller relative to the bigger end is expressed as

F1/A1=F2/A2

substitute we have

800/314.2=F2/1963.75

cross multiply we have

F2=800*1963.75/314.2

F2=1571000/314.2

F2=5000N

F2=5kN

The larger Force is 5kN