A 1200kg car traveling at 45m/s slams on its breaks and slides to a stop. If the coefficient of kinetic friction between the car and the road is 0.85 determine how far the car s…

Question

asked Oct 7, 2021 229k views

1 Answer

Tobias Brandt · Answer 1 · 2021-10-11T21:05:27+0000

Given :

A 1200 kg car travelling at 45 m/s slams on its breaks and slides to a stop.

If the coefficient of kinetic friction between the car and the road is 0.85 .

To Find :

How far the car slides.

Solution :

Acceleration is given by :

$ma = \mu_kmg\\\\a = \mu_kg\\\\a = 0.85* 10\ m/s^2\\\\a = 8.5\ m/s^2$

Distance covered is :

$2as=u^2-v^2\\\\s = (u^2-v^2)/(2a)\\\\s=(45^2-0^2)/(2* 8.5)\\\\s=119.12\ m$

Therefore, distance covered is 119.12 m.

Hence, this is the required solution.