Question

A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take the SAT. The average math score is 517, with s = 90. Assuming µ = 500 for the math SAT, test the null hypothesis. Did training significantly improve scores (α = .05, directional)?

Answer 1

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Explanation:

Step(i):-

Given sample mean (x⁻ ) = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

Null Hypothesis :- H₀ : (μ) =500

Alternative Hypothesis : H₁ : μ ≠ 500

Step(ii):-

Test statistic

`t = (x^(-) -mean)/((s)/(√(n) ) )`

`t = (517 -500)/((90)/(√(100) ) )`

t = 1.717

Level of significance

∝ = 0.05

t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Conclusion:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores