Question

What is the final velocity of a car that has an initial velocity of 15.2 m/s and accelerates at 3.2 m/s^2 for 2.6 seconds?

Answer 1

t=2.59s

Explanation:

v=23.5m/s u=15.2m/s a=3.2m/s^2 t=?

using equation v=u+at t=(v-u)/a t= (23.5-15.2)/3.2=8.3/3.2=2.59s

Answer 2

For this question we should apply
v = u + at
Given : u = 15.2 m/s
a = 3.2 m/s^2
t = 2.6 seconds
Answer :-)
v = u + at
v = 15.2 + 3.2(2.6)
v = 15.2 + 8.32
v = 23.52 m/s

Therefore , the answer is
v = 23.52 m/s