Question

The air in a tire pump has a volume of 1.50L at a temperature of 5◦C. If the temperature is increased to 30◦C and the pressure remains constant, what is the new volume? Hurry Please!

Answer 1

1.6L

Step-by-step explanation:

Given parameters:

Initial volume = 1.5L

Initial temperature = 5°C = 5 + 273 = 278K

Final temperature = 30°C = 30 + 273 = 303K

Unknown:

Final or new volume = ?

Solution;

Since pressure is constant, we simply apply Charles's law to solve this problem.

Using the expression below,

`(V_(1) )/(T_(1) )` =
`(V_(2) )/(T_(2) )`

V and T are volume and temperature

1 and 2 are initial and final states

Insert the parameters and solve;

`(1.5)/(278)` =
`(V_(2) )/(303)`

278V₂ = 1.5 x 303

V₂ = 1.6L