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32 votes
32 votes
HELP ME ASAP 50 POINTS​

HELP ME ASAP 50 POINTS​-example-1
User Keltar Helviett
by
2.8k points

2 Answers

9 votes
9 votes

Answer:

See below ~

Explanation:

Let's get started!

Part (a) :

Statement 1 : ∠A = ∠E = 90° (indicated in diagram)

Statement 2 : ∠C = ∠C (common angle)

ΔABC ~ ΔBDC (AA similarity)

Part (b) :

Now that we have proved the triangles to be similar, we can take their corresponding sides in proportion.


(EC)/(AC) = (ED)/(AB)


(160)/(160+50) = (120)/(AB)


(16)/(21) = (120)/(AB)


AB = (120*21)/(16)


AB = (2520)/(16)

⇒ AB = 157.5

User Marco Ancona
by
3.1k points
19 votes
19 votes

Let's use Thales theorem

  • AC/AB=CE/DE
  • 50+160/AB=160/120
  • 210/AB=4/3
  • 4AB=630
  • AB=630/4
  • AB=157(Approx)
User Sourcerebels
by
3.1k points