Answer:
Explanation:
How many x-intercepts?
Factoring this polynomial eases the job of counting the intercepts.
f(x)=x^4-5x^2 = x^2(x^2 - 5)
Setting x^2 = 0 leads to two x-intercepts: (0, 0) and (0, 0) (a double root).
Setting x^2 - 5 = 0 yields the intercepts (-√5, 0) and (√5, 0).
Thus, there are, strictly speaking, FOUR x-intercepts. Of these, three are immediately visible.