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A small car uses about 130000J of energy in the form of gasoline. The car converts that energy to a kinetic energy of 53000J. What is the efficiency of this conversion?
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A small car uses about 130000J of energy in the form of gasoline. The car converts that energy to a kinetic energy of 53000J. What is the efficiency of this conversion?

User Mordi
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1 Answer

2 votes

Step-by-step explanation:

Given parameters:

Energy input = 130000J

Energy output = 53000J

Unknown:

Efficiency of the conversion = ?

Solution:

Efficiency is the percentage of work output to work input;

Mathematically;

Efficiency = Energy output/ Energy input x 100

Efficiency = 53000/130000 x 100 = 40.8%

User Cordsen
by
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