Question

Is 3.5:

Aqueous solutions of iron(III) bromide and ammonium carbonate react to form a precipitate. Answer the follwing
questions with regards to this reaction.
a) Write the molecular equation for this reaction by
Translating the two reactants into their chemical formulae.
Predict the products.
Label all the states.
Balance the reaction.

Answer 1

A student requested the balanced molecular equation for the reaction between aqueous iron(III) bromide and ammonium carbonate, resulting in the formation of iron(III) carbonate precipitate and ammonium bromide. The balanced equation is FeBr3(aq) + (NH4)2CO3(aq) → Fe2(CO3)3(s) + 6 NH4Br(aq), with states indicated for all compounds.

Step-by-step explanation:

The question asks for the balanced molecular equation for the reaction between aqueous solutions of iron(III) bromide and ammonium carbonate, which leads to the formation of a solid precipitate.

Firstly, we translate the reactants into their chemical formulae:

• 
  
• Iron(III) bromide - FeBr3
• 
  
• Ammonium carbonate - (NH4)2CO3

Predicting the products, we expect iron(III) carbonate to be the precipitate and ammonium bromide to remain in the solution.

The balanced molecular equation is:

FeBr3(aq) + (NH4)2CO3(aq) → Fe2(CO3)3(s) + 6 NH4Br(aq)

FeBr3 is in aqueous solution (aq), (NH4)2CO3 is also in aqueous solution (aq), Fe2(CO3)3 is the precipitate (s) which means it's a solid, and NH4Br remains in the solution (aq).

The reaction is balanced with one mole of iron(III) bromide reacting with one mole of ammonium carbonate to produce one mole of iron(III) carbonate and six moles of ammonium bromide.

Answer 2

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)

Step-by-step explanation:

Aqueous solutions of iron(III) bromide and ammonium carbonate react. This is a double displacement reaction that gives place to ammonium bromide and iron (III) carbonate. Iron (III) carbonate is insoluble so it precipitates. The corresponding molecular equation is:

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)