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Solve -3x=2x^2-4 using quadratic formula

User Corpo
by
8.5k points

1 Answer

3 votes

Answer:


x=-2.35078, 0.850781

General Formulas and Concepts:

Pre-Algebra

  • Order of Operations: BPEMDAS

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula:
    x=(-b\pm√(b^2-4ac) )/(2a)

Explanation:

Step 1: Define equation

-3x = 2x² - 4

Step 2: Rewrite into Standard Form

0 = 2x² + 3x - 4

Step 3: Define variables

a = 2

b = 3

c = -4

Step 4: Find x

  1. Substitute:
    x=(-3\pm√(3^2-4(2)(-4)) )/(2(2))
  2. Evaluate:
    x=(-3\pm√(9-4(2)(-4)) )/(2(2))
  3. Multiply:
    x=(-3\pm√(9+32) )/(4)
  4. Add:
    x=(-3\pm√(41) )/(4)
  5. Evaluate:
    x=(-3\pm6.40312)/(4)
  6. Evaluate:
    x=-2.35078, 0.850781

And we have our final answer!

User Arunkvelu
by
8.4k points

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