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What is the molarity of a solution that contains 10 g of NaOH in 689 mL of solution?​

1 Answer

11 votes

Answer:

0.363 M

Step-by-step explanation:

The equation used to find the molarity is:

Molarity (M or moles/L) = moles / volume (L)

You have not been given values that can be directly substituted into the equation. However, these values can be converted to fit the equation. To find the molarity of the solution, you need to (1) convert grams NaOH to moles (via molar mass from periodic table), then (2) convert mL to L (by dividing by 1,000), and then (3) calculate the molarity (using the molarity formula).

Step 1:

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

10 g NaOH 1 mole
---------------- x ------------------- = 0.2500 moles NaOH
39.996 g

Step 2:

689 mL / 1,000 = 0.689 L

Step 3:

Molarity = moles / volume

Molarity = 0.2500 moles / 0.689 L

Molarity = 0.363 moles/L

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