Question

3.How many grams of lithium nitrate will be needed to

make 250 grams of lithium sulfate? Using the following
equation:
Pb(SO ), + 4 LINO - Pb(NO3), + 2 Li SO
4

Answer 1

`m_(LiNO_3)=314gLiNO_3`

Step-by-step explanation:

Hello!

In this case, for the given chemical reaction:

`Pb(SO_4 )_2, + 4 LiNO_3 \rightarrow Pb(NO_3)_4, + 2 Li_2 SO_4`

We can see a 4:2 mole ratio between lithium nitrate (68.946 g/mol) and lithium sulfate (109.94 g/mol); in such a way, via stoichiometry, the required mass of lithium nitrate to make 250 g of lithium sulfate turns out:

`m_(LiNO_3)=250gLi_2SO_4*(1molLi_2SO_4)/(109.94gLi_2SO_4) *(4molLiNO_3)/(2molLi_2SO_4) *(68.946gLiNO_3)/(1molLiNO_3)\\\\m_(LiNO_3)=314gLiNO_3`

Best regards!