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The pair of points lies on the same line with the given slope. Find x.

(3,-8),(x,-18); slope = -2

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if the gradient is -2 that just means we work back the way, the method i use to find the gradient is y^2-y^1/x^2-x^1 so if we sub the variables in that gives us -18-(-8)/3-x so if we add that up we get -10/3-x, so what has to be on the bottom to get -2? in this case it would be -2 so the overall answer would be -10/5 which would give us a slope of -2 when simplified :) hope this helps
User Sebster
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