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A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T. What is the period if the mass is doubled to 2M
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A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T. What is the period if the mass is doubled to 2M

User Kikkpunk
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1 Answer

5 votes

Answer:

T' = o.707T

Step-by-step explanation:


T = 1/2\pi √(k/m) \\\\m'=2m then\\T' = 1/2\pi √(k/m')\\ = 1/2\pi √(k/2m)\\T' = ((1/2\pi √(k/m)\\))/(1.4) T' = (T)/(1.4)\\T' = 0.707T

User Charrison
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