Question

A soccer ball is kicked at an angle of 40 degrees with an initial velocity of

14 m/s. What is the horizontal velocity in m/s? (Do not state units, and give
answers to the hundredths place.) *

Answer 1

`v_x=10.72\ m/s`

Step-by-step explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, and θ the initial launch angle, the two components of the velocity are given by:

`v_x=v_o\cos\theta`

`v_y=v_o\sin\theta-g.t`

The soccer ball is kicked at an angle of 40° with an initial speed of vo=14 m/s.

The horizontal component is:

`v_x=14\cos 40^\circ`

Calculating:

`v_x=14\cdot 0.766`

`\mathbf{v_x=10.72\ m/s}`