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Hemophilia is a recessive sex-linked disorder (Xh). A man with hemophilia and a female carrier are concerned about their daughter inheriting the disorder. Use a punnett square explain to these parents the probability (percent chance) that their daughter could have the disorder. ​

User Bob Dem
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Answer:

The chances of a hemophilic man and a female carrier having a that one of their daughters inherits the disease are 25%.

Step-by-step explanation:

Since hemophilia is a disease with a sex-linked recessive inheritance pattern —X chromosome— all males who acquire the altered gene will have hemophilia (
X^(h)Y), while a female should have both altered chromosomes (
X^(h)X) to manifest the disease.

If a hemophilic male and a female carrier of the hemophilia gene have children, the possibility of having a daughter with hemophilia can be seen by crossing.


  • X^(h)Y

  • X^(h)X

Alleles
X^(h) Y


X^(h)
X^(h)
X^(h)
X^(h)Y

X
X^(h)X XY

In the offspring, there are:

  • Healthy sons 25%.
  • Hemophilic sons 25%.
  • Carrier daughters 25%.
  • Hemophilic daughters 25%.

The hemophilic man and the carrier woman should know that they have a 25% chance of having a hemophilic daughter, or that 50% of their daughters may have the disease.

User Don Rhummy
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