Question

what is the equation for the line that passes through the given point and is parallel to the graph of y=2/3x+19; (-9, 4)​

Answer 1

Explanation:

We're given the line

`y = (2)/(3)(x) + 19`

The slope of the line is
`(2)/(3)`

We have to find another line with the same slope that goes through the point

`(-9, 4)`. We can solve this by using

`y = mx + b\\y = (2)/(3)(x) + b\\4 = (2(-9))/(3) + b\\4 = -6+ b\\b = 10\\\\y = (2)/(3)(x) + 10`