Question

If 11.9 kJ are used to heat a sample of water the temperature increases from 20.0°C to

650°C. Calculate the mass of the water
general formula

Answer 1

`m=4.51g`

Step-by-step explanation:

Hello!

In this case, since the energy involved during a heating process is shown below:

`Q=mCp\Delta T`

Whereas the specific heat of water is 4.184 J/(g°C), we can compute the heated mass of water by the addition of 11.9 kJ (11900 J) of heat as shown below:

`m=(Q)/(Cp\Delta T)`

Thus, by plugging in, we obtain:

`m=(11900J)/(4.184(J)/(g\°C)(650\°C-20.0\°C))\\\\m=4.51g`

Best regards!