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5x^2+3x-3=0 using equation method​

User Pu
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1 Answer

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Answer:

x = (-3±√69)/10

Explanation:

Perhaps you want to find the solutions using the quadratic formula.

For the equation ...

ax² +bx +c = 0

The solution is given by the formula ...


x=(-b\pm√(b^2-4ac))/(2a)

Here, we have a=5, b=3, c=-3, so the values of x are ...


x=(-3\pm√(3^3-4(5)(-3)))/(2(5))\\\\\boxed{x=(-3\pm√(69))/(10)}

User Luke Morgan
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