24.5k views
3 votes
If f(x) = -x^2 + 6x - 1 and g(x) = 3x^2 - 4x-1, find (f - g)(x).

A. (f- g)(x) = -4x^2 - 2x
B. (f- g)(x) = 2x^2 + 2x-2
C. (f- g)(x) = 4x^2 - 10x
D. (f - g)(x) = -4x^2 + 10x

User Olvagor
by
6.8k points

1 Answer

7 votes

Answer:D

Explanation:

(f-g)(x)= -x^2+6x-1- (3x^2-4x-1)

(f-g)(x)= -x^2+6x-1 -3x^2+4x+1

(f-g)(x)= -x^2-3x^2+6x+4x-1+1

(f-g)(x)= -4x^2+10x

User Avishorp
by
6.1k points