Answer:
37.5%
Explanation:
The computation is shown below:
Here we assume that the 1st, 2nd and 3rd child be the triplet and it could be either a girl or boy
Now
B = Boy
G = Girl
The possible triplets are
(BBB) (BBG) (BGB) (BGG) (GBB) (GBG) (GGB) (GGG)
These are 8 triplets
Now find the sets that involves 2 boys and a girl
(BBG) (BGB) (GBB)
Now the probability is
P = 3 ÷ 8
= 37.5%