Question

A gas has a volume of 0.550 l at a temperature of -55.0 c. what will the volume be if the temperature is increased to 30.0 c and the pressure remains constant?

Answer 1

Gay-Lussac's law:
`(V1)/(T1)`=
`(V2)/(T2)`

We need to convert temperature from Celsius to Kelvin

-55 C = 218 K

30 C = 303 K

V2 = V1*T2 / T1 = 0.550 *303 / 218 = 0.764 l