Answer:
concentration of Ag = 1.34 g / L .
Step-by-step explanation:
Quantity of charge = 2.35 x 60 x 2.12 = 298.92 coulomb.
equivalent weight of silver = 108 g .
96500 coulomb deposits 108 g of silver
298.92 coulomb will deposit 108 x 298.92 / 96500 g
= .3345 g . of silver .
.250 L contains .3345 g of silver
1 L contains .3345 x 4 = 1.34 g
concentration of Ag = 1.34 g / L .