Answer:
(5, 1 ) and (3, 1 )
Explanation:
2x - 3y = 7 → (1)
- 3x + 7y = - 8 → (2)
multiplying (1) by 3 and (2) by 2 and adding will eliminate x
6x - 9y = 21 → (3)
- 6x + 14y = - 16 → (4)
add (3) and (4) term by term to eliminate x
0 + 5y = 5
5y = 5 ( divide both sides by 5 )
y = 1
substitute y = 1 into either of the 2 equations and solve for x
substituting into (1)
2x - 3(1) = 7
2x - 3 = 7 ( add 3 to both sides )
2x = 10 ( divide both sides by 2 )
x = 5
solution is (5, 1 )
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4x - 3y = 9 → (1)
2x + 3y = 9 → (2)
adding the 2 equations term by term will eliminate y
6x + 0 = 18
6x = 18 ( divide both sides by 6 )
x = 3
substitute x = 3 into either of the 2 equations and solve for y
substituting into (2)
2(3) + 3y = 9
6 + 3y = 9 ( subtract 6 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
solution is (3, 1 )