196k views
13 votes
Maggie rides her bike down a hill. She starts from rest and accelerates

at a rate of 2.5 m/s/s. If she reaches the bottom of the hill with a final
velocity of 38 m/s, how long is the hill?

User Woodifer
by
5.1k points

2 Answers

12 votes

Answer:

288.8 m

Step-by-step explanation:

v² = u² + 2as

v= final velocity= 38m/s

u = initial velocity = 0 m/s

a= acceleration= 2.5 m/s²

s = distance = ?

User Abhishek Kamal
by
5.7k points
11 votes

Answer:

288.8 m

Step-by-step explanation:

v² = u² + 2as

  • v= final velocity= 38m/s
  • u = initial velocity = 0 m/s
  • a= acceleration= 2.5 m/s²
  • s = distance = ?


s = (v^(2) - u^(2) )/(2 a) \\\\\\s = (38^(2) )/(2* 2.5)\\\\ \\s = 288.8m

User Drew Cordano
by
4.8k points