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A firefighter of mass 75 kg slides down a pole. The force of friction is 400N. What is the firefighter's acceleration as they slide down the pole?

User Akeshet
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1 Answer

5 votes

Answer:

a = 5.33 [m/s²]

Step-by-step explanation:

To solve this problem we must use Newton's second law which tells us that the sum of the forces acting on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force = 400 [N]

m = mass = 75 [kg]

a = F/m

a = 400/75

a = 5.33 [m/s²]

User John Myles White
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