Question

A line passes through tge points (1,-3) and (4,6) what is the zero of this line ?

Answer 1

The zero of the line is (2,0)

Explanation:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as:

`\displaystyle y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

We are given the points (1,-3) and (4,6). Substituting:

`\displaystyle y+3=(6+3)/(4-1)(x-1)`

Operating:

`\displaystyle y+3=(9)/(3)(x-1)`

`y+3=3(x-1)`

The zero of this line can be found by making y=0 and solving for x:

0+3=3(x-1)

3=3x-3

Adding 3:

6=3x

Solving:

x = 2

The zero of the line is (2,0)