Question

A rectangle has a length that is 7 inches less that twice it's width. The area of the rectangle is 72 square inches. Write an equation that represents this solution.

Answer 1

Answer:
`2x^2-7x=72` , where x= width of the rectangle ( in inches).

Explanation:

Let x= width of the rectangle ( in inches).

Then its length = 2x-7 ( in inches).

Area of rectangle = Length × width

= (2x-7) × (x)

= 2x × x -7 ×x

= 2x²-7x

The area of the rectangle is 72 square inches.

`\Rightarrow\ 2x^2-7x=72`

Hence, the equation that represents the given situation :

`2x^2-7x=72`