A rectangle has a length that is 7 inches less that twice it's width. The area of the rectangle is 72 square inches. Write an equation that represents this solution.

Question

asked Jan 6, 2021 159k views

1 Answer

Waldo · Answer 1 · 2021-01-09T22:25:53+0000

Answer:
2x^2-7x=72 , where x= width of the rectangle ( in inches).

Explanation:

Let x= width of the rectangle ( in inches).

Then its length = 2x-7 ( in inches).

Area of rectangle = Length × width

= (2x-7) × (x)

= 2x × x -7 ×x

= 2x²-7x

The area of the rectangle is 72 square inches.

$\Rightarrow\ 2x^2-7x=72$

Hence, the equation that represents the given situation :

2x^2-7x=72