Answer:
70.3m
Explanation:
The set up will be a right angled tringle with angle of elevation of 8°.
The distance you are standing from the rocket (adjacent) = 500m
The height of the rocket (opposite) = x
Using the SOH CAH TOA trig identity;
According to TOA
tan(theta) = opp/adj
tan 8 = x/500
x = 500tan8
x = 500(0.1405)
x = 70.27
x = 70.3m (to the nearest tenth)
Hence the height of the rocket in meters is 70.3m