Complete question :
In one year, the population of Douglas, the former copper mining town on the U.S.-Mexico border, shrunk by 200. Over the last ten years, the town’s population is going down at an average rate of 1.16% per year. Douglas’ current population in November 2020 is 15,140. a. Write an equation to model the population decay of Douglas using the data given. b. If the town’s population loss continues to occur at this rate, what will the population of Douglas in 6 months from now? Round your answer to the nearest integer. c. If the town’s population loss continues to occur at this rate, what will the population of Douglas in one year? Round your answer to the nearest integer. d. If the town’s population loss continues to occur at this rate, what will the population of Douglas in November 2027? Round your answer to the nearest integer.
Answer:
15052 ; 14,964 ; 13953
Explanation:
Given that:
Rate of population decline = 1.16% annually
Population in November 2020 = 15140
A = I(1 - r)^t
Where ;
A = final population
I = initial population
r = rate of decline
t = number of years
Population in 6 months
t = 6 months = 0.5 year, r = 1.16% = 0.0116
A = 15140(1 - 0.0116)^0.5
A = 15140(0.9884)^0.5
A = 15051.931
A = 15052 ( nearest integer)
Population after 1 year :
A = 15140(1 - 0.0116)^1
A = 15140(0.9884)^1
A = 14964.376
A = 14964 ( nearest integer)
Population in 2027:
t = 2027 - 2020
A = 15140(1 - 0.0116)^7
A = 15140(0.9884)^7
A = 13952.596
A = 13953 ( nearest integer)