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2. How many atoms of zinc are present in 0.48 mol of zinc?
(show solution)​

User Chedabob
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1 Answer

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Answer:

2.89× 10²³ atom of Zn

Explanation:

Given data:

Number of moles of Zn = 0.48 mol

Number of atoms of Zn = ?

Solution:

Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atom

0.48 mol × 6.022 × 10²³ atom / 1mol

2.89× 10²³ atom

User Whitneyit
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