Question

4/5 of Peter's money is twice as much as Weimin's money. What fraction of Peter's money is Weinim's money?

Answer 1

Answer:
`\frac25`

Explanation:

As per given,

`\frac45*(\text{Peter's money})=2 (\text{Weimin's money})`

Let x= Weimin's money

Then
`\frac45*(\text{Peter's money})=2x`

`\text{Peter's money}=2x*\frac54\\\\\Rightarrow\ \text{Peter's money}=\frac52x`

The required fraction=
`\frac{\text{Weinim's money}}{\text{Peter's money}}`

`=(x)/((5)/(2)x)=(1)/(\frac52)\\\\\\=\frac25`

Hence, Required fraction =
`\frac25`