menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Vanessa has 23 coins in nickels and dimes and has $1.50 in all. Which equation could be used to find the number of nickels, n? A. 5n + 10 (23) = 1.50 B.5n + 10 (23 – n) = 1.50 C. 0.05%+0.10 (23 – 1) =
asked
Jun 19, 2021
115k
views
2
votes
Vanessa has 23 coins in nickels and dimes and has $1.50 in all. Which equation could
be used to find the number of
nickels, n?
A. 5n + 10 (23) = 1.50
B.5n + 10 (23 – n) = 1.50
C. 0.05%+0.10 (23 – 1) = 1.50
D. 0.05m+0.10 (m - 23) = 1.50
Mathematics
high-school
Carlo Field
asked
by
Carlo Field
7.3k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
4
votes
Answer:
a
Explanation:
Erosman
answered
Jun 26, 2021
by
Erosman
8.1k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
Related questions
asked
Nov 22, 2017
154k
views
Vanessa has 287 pennies. She has 178 fewer nickels than pennies. She has 100 fewer dimes than nickels. How many dimes does Vanessa have?
Gangsta
asked
Nov 22, 2017
by
Gangsta
7.7k
points
Mathematics
high-school
2
answers
3
votes
154k
views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.5m
questions
12.2m
answers
Other Questions
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org