Question

1. A cyclist accelerates from 7 m/s to 11 m/s in two seconds. What is his acceleration?
m/s/s

Answer 1

`\boxed {\boxed {\sf 2 \ m/s^2}}`

Step-by-step explanation:

Acceleration can be found by dividing the change in velocity by the time.

`a=(v_f-v_i)/(t)`

The final velocity is 11 meters per second and the initial velocity is 7 meters per second. The time is 2 seconds.

`v_f=11 \ m/s\\v_i=7 \ m/s\\t= 2 \ s`

Substitute the values into the formula.

`a=(11 \ m/s-7 \ m/s)/(2 \ s)`

Solve the numerator.

• 11 m/s - 7 m/s = 4 m/s

`a=(4 \ m/s)/(2 \ s)`

Divide.

`a= 2 \ m/s/s` or
`a= 2 \ m/s^2`

The acceleration of the cyclist is 2 meters per second squared.