Question

A Chevy Camaro drives straight off the top level off a parking garage at 9 m/s. If the car landed 81 meters away from the base of the parking garage, how high (height) was the top level? 196.9 meters 296.9 meters 396.9 meters 496.9 meters​

Answer 1

The correct option is c: 396.9 meters.

Explanation:

First, we need to find the time at which the car landed:

`v = (x)/(t)`

`t = (x)/(v) = (81 m)/(9 m/s) = 9 s`

Now, we can find the height of the top-level:

`y_(f) = y_(0) + v_{0_(y)}t - (1)/(2)gt^(2)`

Since the car has only a velocity in the horizontal direction, we have:

`0 = y_(0) + 0*t - (1)/(2)gt^(2)`

`y_(f) = (1)/(2)gt^(2) = (1)/(2)9.81 m/s^(2)*(9 s)^(2) = 397 m`

Therefore, the correct option is c: 396.9 meters.

I hope it helps you!