Question

2.83 kJ are added to a sample of water at 100°C and it completely vaporizes. What is the

mass of the water?
general formula

Answer 1

0.0013kg

Step-by-step explanation:

Given parameters:

Quantity of heat = 2.83kJ

Temperature = 100°C

Unknown:

Mass of the water = ?

Solution:

The amount of heat needed to vaporize a substance is dependent on the mass of the substance and its latent heat of vaporization.

H = mL

H is the amount of heat

m is the mass

L is the latent heat of vaporization

Latent heat of vaporization of water = 2260 kJ/kg

Now insert the parameters and solve;

2.83 = m x 2260

m =
`(2.83)/(2260)` = 0.0013kg