Question

Katrina wrote the standard form of a linear equation as 4x-2/3y=8. Sophia told her that the equation was not yet in standard form in over the right advice for how to fix it what advice did Sophia give to Katrina

A. Multiply both sides of the equation by three the standard form of the equation is 12x-2y=24.
B. Multiply both sides of the equation by three and then divide both sides by to the standard form of the equation is 6x-y=12
C. Multiply both sides of the equation by three the standard form of the equation is 12 X minus 2Y equals X
D. Multiply both sides of the equation by three and then divide both sides by to the standard form of the equation is 6X minus Y equals 4

Answer 1

9514 1404 393

Answer:

multiply by 3 and divide by 2 to get 6x -y = 12.

Explanation:

A standard form equation has mutually prime integers for coefficients, and the leading one is positive. We can get that here by multiplying by 3 (to eliminate the denominator) and dividing by 2 (to remove that common factor). The result is ...

4(3/2)x -(2/3)(3/2)y = 8(3/2)

6x -y = 12