Question

The sum of three consecutive integers is more than 62. Write an inequality to represent the above

situation then solve your inequality.

Answer 1

Given:

Sum of three consecutive integers is more than 62.

To find:

The inequality to represent the above situation then solve your inequality.

Solution:

Let the three consecutive integers are
`x,x+1,x+2` respectively.

Sum of three consecutive integers is more than 62. So,

`x+(x+1)+(x+2)>62`

`3x+3>62`

Subtract 3 from both sides.

`3x>62-3`

`3x>59`

Divide both sides by 3.

`x>(59)/(3)`

Therefore, the required inequality is
`x+(x+1)+(x+2)>62` and solution is
`x>(59)/(3)`.