Answer:
Yes.
Explanation:
When the function f(x) = −2x³ + 17x² − 64 is divided by x − 8, the remainder is zero. Therefore, x − 8 is a factor of f(x) = −2x³ + 17x² − 64.
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yes
x-8 will be a factor if f(8) = 0.
f(8) = -2(8^3) +17(8^2) -64 = 64(-16 +17 -1) = 0
Yes, x-8 is a factor.
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