Question

A 2.0 kg box is pulled along a frictionless, horizontal surface by a force that makes an angle of 30 degrees with the ground. If the box is pulled a distance of 4.0 meters and changes speed from 1.0 m/s to 3 m/s, what was the magnitude of the force on the box?

Answer 1

2 N

Step-by-step explanation:

v = Final velocity = 3 m/s

u = Initial velocity = 1 m/s

s = Displacement = 4 m

m = Mass of box = 2 kg

Acceleration of the box is

`v^2-u^2=2as\\\Rightarrow a=(v^2-u^2)/(2s)\\\Rightarrow a=(3^2-1^2)/(2* 4)\\\Rightarrow a=1\ \text{m/s}^2`

Force is given by

`F=ma\\\Rightarrow F=2* 1\\\Rightarrow F=2\ \text{N}`

The force on the box is 2 N.