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Find the value of y in the solution to the system of equations shown.

y = 4x - 28
y = 1.5x - 18

User Haylie
by
7.7k points

2 Answers

5 votes

Answer:


y=-12

Explanation:

Given system of equations:


\begin{cases}y = 4x - 28\\y = 1.5x - 18\end{cases}

Use the method of substitution to solve for x:


\begin{aligned}y & = y\\\implies 4x-28 & = 1.5x - 18\\4x-1.5x & = -18+28\\2.5x & = 10\\x & = 10 / 2.5\\x & = 4\end{aligned}

Substitute the found value of x into one of the equations and solve for y:


\begin{aligned} y & = 4x-28\\\implies y & =4(4)-28\\y & = 16-28\\y & = -12\end{aligned}

User TeoREtik
by
9.1k points
10 votes

Answer: y = -12

Equation's:

  1. y = 4x - 28
  2. y = 1.5x - 18

Solve them simultaneously:

4x - 28 = 1.5x - 18

4x - 1.5x = -18 + 28

2.5x = 10

x = 10/2.5 = 4

Now find the value of y:

y = 4x - 28

insert x = 4

y = 4(4) - 28

y = 16 - 28 = -12

User Fantasticrice
by
7.8k points

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