Answer:
Chemical equation: AgNO3 + LiBr -> AgBr + LiNO3
Complete Ionic equation: Ag + NO3 + Li + Br -> AgBr + Li + NO3
Net Ionic equation: Ag + Br -> AgBr
Step-by-step explanation:
You start out with the chemical equation. We know that to get to the complete ionic equation we have to follow the solubility guidelines for common ionic compounds. In there, we can see that NO3 is soluble with no exceptions, which means every NO3 in this equation should be separated from the compound (this brings us to Ag + NO3 + LiBr -> AgBr + Li + NO3). Next we should separate Br, but be careufl because in the solubility guidelines it states that an exception to this being soluble would be if Br was next to Ag, Hg, and Pb. Since our second Br is next to an Ag, our equation will look like Ag + NO3 + Li + Br -> AgBr + Li + NO3. To find the net ionic equation all we're going to need to find are the substances that cancel each other out on both sides of the equation (aka the spectator ions). Our spectator ions in this case are Li and NO3. After we cancel those out, our net ionic equation is Ag + Br -> AgBr.