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What volume of 18.5 M nitric acid would be needed to make 25.0 mL of 3.0M?

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Answer:What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution? 903 mL What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

Step-by-step explanation:

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