167k views
21 votes
NEED ANSWER ASAP HELP

Given ABC with altitude h
Prove: sin(B)/b=sin(C)/c

NEED ANSWER ASAP HELP Given ABC with altitude h Prove: sin(B)/b=sin(C)/c-example-1

2 Answers

5 votes

Final answer:

To prove that sin(B)/b = sin(C)/c in triangle ABC with altitude h, we can use the law of sines. The law of sines states that the ratio of the length of a side to the sine of its opposite angle is the same for all three sides.

Step-by-step explanation:

To prove that sin(B)/b = sin(C)/c in triangle ABC with altitude h, we can use the law of sines. The law of sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is the same for all three sides.

Therefore, we have:

sin(B)/b = sin(C)/c

which means that the ratio of sine of angle B to the length of side b is equal to the ratio of sine of angle C to the length of side c.

User Nathan Liang
by
5.7k points
12 votes
  • Multiple property of equality
  • csin(B) = bsin(C)
  • Division property of equality

NEED ANSWER ASAP HELP Given ABC with altitude h Prove: sin(B)/b=sin(C)/c-example-1
NEED ANSWER ASAP HELP Given ABC with altitude h Prove: sin(B)/b=sin(C)/c-example-2
User RoiHatam
by
5.7k points