Answer:
(p -3q )(p -3q )
Explanation:
p'2 - 6pq + 9q'2
find two values that add to give 6 and multiply to 9
p x p =p'2
-3q x p = -3pq -3 x pq = -3pq ...... -3pq - 3pq = -6pq
-3q x - 3q = 9q'2
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